fix C++11 error with constexpr

error: constexpr function's return type 'std::vector<TypeInfo>' is not a literal type

Change-Id: I3f0e2ac5ba0330698052db962a3ca4b81b3edb39
Signed-off-by: Gregg Reynolds <reynolds-gregg@norc.org>
Reviewed-on: https://gerrit.iotivity.org/gerrit/8487Tested-by: jenkins-iotivity <jenkins-iotivity@opendaylight.org>
Reviewed-by: Phil Coval <philippe.coval@osg.samsung.com>
Reviewed-by: Ziran Sun <ziran.sun@samsung.com>

service/resource-encapsulation/src/common/primitiveResource/src/RCSResourceAttributes.cpp

@@ -206,7 +206,7 @@ namespace
     };
 
     template< typename VARIANT, int POS >
-    constexpr inline std::vector< TypeInfo > getTypeInfo(Int2Type< POS >) noexcept
+    inline std::vector< TypeInfo > getTypeInfo(Int2Type< POS >) noexcept
     {
         auto vec = getTypeInfo< VARIANT >(Int2Type< POS - 1 >{ });
         vec.push_back(TypeInfo::get< VARIANT, POS >());
@@ -214,7 +214,7 @@ namespace
     }
 
     template< typename VARIANT >
-    constexpr inline std::vector< TypeInfo > getTypeInfo(Int2Type< 0 >) noexcept
+    inline std::vector< TypeInfo > getTypeInfo(Int2Type< 0 >) noexcept
     {
         return { TypeInfo::get< VARIANT, 0 >() };
     }